When the temperature is raise from 300 K to 400 K the rate of a reaction is increased by `10^(8)` times. What is the energy of activation?

Options

A. 44.1 Kcal
B. 22.5 Kcal
C. 28.2 Kcal
D. 18.6 Kcal

Answer

A

Explanation

`log((K_(2))/K)=(Ea)/(2.303R)(1/(T_(1))-1/(T_(2))),log_(10)10^(8)=(epsilon_(8))/(2.303xx2)(1/300-1/400)`
`8xx1=(epsilon_(a))/(2.303xx2)xx((400-300)/(300xx400)),epsilon_(a)=(8xx2.303xx2xx300xx400)/100=44217.6` cal =44.2176 Kcal