The inversion of cane sugar proceeds with half life of 500 minute at pH=5 for any concentration of sugar. However if pH=6 the half life changes to 50 minutes. The rate law expression for sugar inversioncan be written as

Options

A. `r=K["sugar"]^(2)[H^(+)]^(0)`
B. `r=k["sugar"]^(1)[H^(+)]^(0)`
C. `r=k["sugar"]^(1)[H^(+)]^(1)`
D. `r=K["sugar"]^(0)[H^(+)]^(1)`

Answer

B

Explanation

`5" "500,((t_(1//2))_(1))/((t_(1//2))_(2))=[([H^(+)]_(2))/([H^(+)]_(1))]^(n-1),(10)^(1)=(10^(-1))^(n-1),(10)^(1)=(10)^((-n+1)),n=0`
`6" "50`