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Hydrogenaton of vegetable thee at 25^(@)...

Hydrogenaton of vegetable thee at` 25^(@)C` reduces pressure of `H_(2)` from 2 atm to 1.2 atm in 50 minute. The rate of reaction in terms of molarity per second is

A

`1.06xx10^(-6)`

B

`1.06xx10^(-5)`

C

`1.06xx10^(-7)`

D

`1.06xx10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
B

`r_(((atm)/t))=r_((M/t))xxRxxT,(r_(mu))/("sec")=0.00325/323=1.006xx10^(-5)`
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