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Elementary unimolecular reaction have fi...

Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanism by imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constant with the experimental rate law.
The decomposition of `O_(3)` obeys the mechanism given below,
Step 1: `O_(3)hArrO_(2)+(O)-` fast
Step 2: `O_(3)+(O)toO_(2)+O_(2)-` slow
`H_(2)+Br_(2)to2HBr`
Mechaism : `Br_(2)hArr2Br` (fast)
`H_(2)+brtoHBr+H`(slow)
`H+BrtoHBR` (Fast)
Order of the reaction is

A

0

B

0.1

C

1.5

D

0.2

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(C)=([Br]^(2))/([Br_(2)])implies[B_(r)]=sqrt(K_(c).[Br_(2)]),r=K_(2).[H_(2)][B_(r)],r=K_(2).[H_(2)](K_(C))^(1/2).[Br_(2)]^(1/2),r=K.[H_(2)]^(1)[Br_(2)]^(1/2)`
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