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The rate of reaction becomes two times f...

The rate of reaction becomes two times for every `10^(@)C` rise in temperature. If the rate of reaction increases by 32 times when the temperature is increased from `30^(@)C` to `(10x)^(2)C`. Then X=

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The correct Answer is:
8
`(r_(2))/(r_(1))=my^(y)implies32=2y,2^(5)=2^(y),y=5`
`=(T_(2)-T_(1))/10y=(T_(2)-30)/10=5,T_(2)=80^(@)C=10x,x=8`
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