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The initial concentration of N(2)O(5) in...

The initial concentration of `N_(2)O_(5)` in the first order reaction`N_(2)O_(5)to2NO_(2)+1/2O_(2)` was `1.24xx10^(-2)` mole /lit at 318 k. The concentration of `N_(2)O_(5)` after 60 min is `0.20xx10^(-2)` mole/lt. Calculate the rate constant of reaction at 318 K

A

`0.0304"min"^(-1)`

B

`0.0602"sec"^(-1)`

C

`0.0802"sec^(-1)`

D

`1.265"min"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Kxxt=2.303xxlog((C_(0))/(C_(t))),Kxx60=2.303xxlog((1.24xx10^(-2))/(0.20xx10^(-2)))`
`K=2.303/50xxlog(6.2)=2.303//60xx0.7924=0.0304`
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