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The rate constants of a reaction at 500 ...

The rate constants of a reaction at 500 k and 700 k are `0.02"sec"^(-1)` and `0.07 "sec"^(-1)` respectively.
Calculate the value of `E_(a)`

A

18230.8J

B

190.83J

C

185.02J

D

172.02J

Text Solution

Verified by Experts

The correct Answer is:
A
`(K_(2))/(K_(1))=(Ae^(-Ea_(2)//RT_(2)))/(Ae^(-Ea//RT_(1))),0.07/0.02=e^((-epsilon_(a))/(RT_(2))+(epsilon_(a))/(RT_(1)))`
`2.303log(7/2)=(E_(a))/R(1/(T_(1))-1/(T_(2))),2.303xx0.544=(E_(a))/R(1/500-1/700)`
`E_(a)=((2.303xx0.544xx8.314xx500xx700)/200)=18228` Joule
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