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A substance A decomposes in solution by ...

A substance A decomposes in solution by following the first order kinetics. Flask I contains 1 L of 1 M of solution of A and flask II contains 100 ml of 0.6 M solution of A. After 8 hrs the concentrationof A is flask I become 0.25 M. What will be time for concentration of A in flask II to become 0.3 M?

A

2.0hrs

B

8.0 hrs

C

4.0hrs

D

6.0 hrs

Text Solution

Verified by Experts

The correct Answer is:
C
Flask-I(A): (`1xx1` )mole (on 1 mole `overset(8hr)(to)(0.25xx1)` mole)
Flask II(A):`((0.6xx100)/1000)` (or) `0.06"mole"overset(t=?)(to)((0.3xx100)/1000)`
`(Kxx8)/(Kxxt)=(log((1xx1)/(0.25xx1)))/(log((0.6xx100//1000)/(0.3xx100/1000))),8/t,(log4)/(log2),8/t=(2log2)/(log2)impliest=8/2=4hr,t=4hr`
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