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The data given below are for the reactio...

The data given below are for the reactionof NO and `Cl_(2)` to form NOCl at 295 K
`[Cl_(2)]" "[NO]" ""initial rate(mol litre"^(-1)"sec"^(-1))`
`0.05" "0.05" "1xx10^(-3)`
`0.15" "0.05" 3xx10^(-3)`
`0.05" "0.15" "9xx10^(-3)`
The reaction rate when conc. of `Cl_(2)` an NO are 0.2 M and 0.4 M respectively is

A

0.256 mole `"litre"^(-1)`

B

0.256 mole `"litre"^(-1)"sec"^(-1)`

C

0.512 mole litre `"sec"^(-1)`

D

0.512 mole `"litre"^(-1)`sec

Text Solution

Verified by Experts

The correct Answer is:
B
`r=K[NO]^(2)[Cl_(2)]^(1)=8xx(0.4)^(2)xx(0.2)^(1)=8xx0.4xx0.4xx0.2=0.256`
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