The threshold frequency of a metal is `1.11 xx 10^(16) Hz`. What is the maximum kinetic energy of the photo electron produced by applying a light of 15 Å on the metal ?

Explanation

`v = (c)/(lambda) = (3.0 xx 10^(8))/(15 xx 10^(-10)m) = 2 xx 10^(17) Hz`
`KE = h v - hv_(0)`
`KE = [6.625 xx 10^(-34) Js xx 2 xx 10^(17) s^(-1)] - [6.625 xx 10^(-34) Js xx 1.11 xx 10^(16) s^(-1)]`
Kientic energy `= 1.25 xx 10^(-16) J`