What is the ratio between the energies of two types of radiation whose wavelengths are 6000 Å and 2000 Å respectively.

Explanation

`lambda_(1) = 6000 Å = 6 xx 10^(-7) m`
`lambda_(2) = 2000 Å = 2 xx 10^(-7) m`
`(E_(1))/(E_(2)) = (h e)/(6 xx 10^(-7)) xx (2 xx 10^(-7))/(h e) = (1)/(3)`
`:. E_(1) : E_(2) = 1:3` or `E_(2) = 3E_(1)`