Calculate the wave number and wave length of `H_(alpha)` line in the Balmer series of hydroge emission spectrum.

Explanation

For `H_(alpha)` line in the Balmer series
`n_(1) = 2` and `n_(2) = 3`
`bar(v) = 109677((1)/(2^(2)) - (1)/(3^(2))) = 15,232.9 cm^(-1)`
`lambda = (1)/(V) = (1)/(15,232.9) = 6.564 xx 10^(-5) cm`
Wave number of `H_(alpha)` line `= 1.5239 xx 10^(4) cm^(-1)`
Wave length of `H_(alpha)` line = 6564 Å