Find the momentum of a particle whose de Broglie wavelength is `1 A^(0)`.

Explanation

de Broglie wave length, `lambda = 1 A^(0) = 1.0 xx 10^(-10)m`
Momentum of a particle , P = ?
`lambda = (h)/(P)` or `P = (h)/(lambda) = (6.625 xx 10^(-34) kgm^(2)s^(-1))/(1.0 xx 10^(-10)m)`
Momentum of a particle is `6.625 xx 10^(-24) kg ms^(-1)`