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When a light of wavelength 300 nm falls ...

When a light of wavelength 300 nm falls on the surface of potassium metal, electrons with kinetic energy of `1.5 xx 10^(5) J mol^(-1)` are emitted, then calculate the minimum energy needed to remove an electron from the metal.

Text Solution

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The correct Answer is:
`4.13 xx 10^(-19)J`
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