Based on reductive ozonolysis reaction, how do you distinguish between an alkene and alkyne?

Explanation

An alkene, on reductive ozonolysis, two carbonyl compounds are formed.
`R-CH=CH-R.underset((ii)H_(2)O,Zn)overset((i)O_(3))rarrR-CHO+R.CHO`
An alkyne, on reductive ozonolysis, a dicarbonyl compound is formed.
`R-C-=C-R.underset((ii)H_(2)O,Zn)overset((i)O_(3))rarrR-underset(O)underset(||)(C)-underset(O)underset(||)(C)-R.`