Acceleration due to gravity at surface of a planet is equal to that at surface of earth and density is 1.5 times that of earth. If radius is R. radius of planet is

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R , the radius of the planet would be

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R , the radius of the planet would be

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R , the radius of the planet would be

The density of a newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth be R, then radius of the planet would be

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at surface of planet is half of the acceleration at surface of earth, if radius of the earth is R. The radius of planet would be

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to gravity at the surface the planet is equal to that at the surface of the earth. If the radius of the earth is R , the radius of the planet would be .......

The acceleration due to gravity at the surface of earth (g_(e)) and acceleration due to gravity at the surface of a planet (g_(p)) are equal. The density of the planet is three times than that of earth. The ratio of radius of earth to the radius of planet will be.

If acceleration due to gravity on the surface of a planet is two times that on surface of earth and its radius is double that of earth. Then escape velocity from the surface of that planet in comparison to earth will be

The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to: