" 25.वह5"y=2x^(2)+3sin x" के "x=0" पर अनिस्लंब की प्रवणता "

Find the slope of the tangent and normal to the following curve. (i) y = 2x^(2) + 3 sin x at x = 0 (ii) y = (sin 2x + cot x + 2)^(2) "at x" = (pi)/(2)

y=sin x, ….. x = 0, x = (2pi)/(3)

2x + 3y = 0 , 3 x + 4y = 5 .

The slope of the normal to the curve y=2x^(2)+3sin x at x=0 is :

The slope of the normal to the curve y=2x^(2)+3sin x at x = 0 is ……….

" If "sin^(2)x+sin x cos x-6cos^(2)x=0" and "-(pi)/(2)ltxlt0," then value of "cos2x" is " -3/5 3/5 -4/5 4/5

If y = a sin x + (5 + 2x) cos x, " then " y'' + y =

2(x-y sin2x)dx+(3y^(2)+cos2x)dy=0