A solution of `Ni(NO_3)_2` is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of nickel is deposited at the cathode?[molar mass of Ni `= 58.7gma " mol"^(-1)`]

Explanation

Therefore mass deposited by
`5 xx 20 xx 60 C = (58.7 xxx 6000)/(2 xx 96500) = 1.84 g`
or `W = Zit`
`w = (29.35 xx 5 xx 20 xx 60)/(96500) = 1.83 g`
Relation used :
Mass of nickel deposited `(W) = (I t E)/(96500) g`.
where Current (i) = 5 amperes
time (t) = 20 minutes
`= 20 xx 60 = 1200 s`
Equivalent mass (E) `= ("Molar mass")/("total (+)ve charge") = (58.7)/(2)`
`=29.35 g mol^(-1)`
or, `W = ("it E")/(96500)`
`= (5 xx 1200 xx 29.35)/(96500)`
Mass of Nickel deposited = 1.8248 g.