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" Evaluate (निकालें) : "int(0)^( pi/2)si...

" Evaluate (निकालें) : "int_(0)^( pi/2)sin2x log tan xdx

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int_(0)^((pi)/(2))sin2x*log(tan x)dx=

int_0^(pi/2)sin2x log(tanx)dx

int_(0)^((pi)/(2))cos2x log sin xdx

int_(0)^( pi/2)x sin xdx

int_(0)^((pi)/(2))sin2x log tan xdx is equal to

int_(0)^(pi//2) sin 2x log tan x dx is equal to

int_(0)^(pi//2) sin 2x log tan x dx is equal to

int_(0)^(pi//2) sin 2x log (tan x) dx is equal to

int_(0)^( pi/4)sin2x sin3xdx

Prove that int_(0)^((pi)/(2))sin2x log tan xdx=0