" The normal at "(1,1)" to the circle "x^(2)+y^(2)-4x+6y-4=0" is "

The equation of the normal at (1,2) to the circle x^(2)-y^(2)-4x-6y-12=0 is

Find where the normal to the circle x^(2)+y^(2)-4x+6y+9=0 is parallel to x-axis.

The equation of the circle with centre (-1,1) and touch the circle x^(2)+y^(2)-4x+6y-3=0 externally is

Find the equation of the normal to the circle x^(2) +y^(2) -4x -6y +11 0 at (3,2) Also find the other where the normal meets the circles.

Find the equation of the normal to the circle x^(2) + y^(2)- 4x-6y+11=0 at (3,2) . Also find the other point where the normal meets the circle.

The lngth of the tangent from the point (1, 1) to the circle x^2 + y^2 + 4x + 6y + 1 = 0 is

The equation of the normal to the circle x^(2)+y^(2)+6 x+4 y-3=0 at (1,-2) is

Locus of point of intersection of perpendicular tangents to the circle x^(2)+y^(2)-4x-6y-1=0 is

Locus of point of intersection of perpendicular tangents to the circle x^(2)+y^(2)-4x-6y-1=0 is