The distance between the object and the screen is d (greater than 4 times the focal length of a convex lens). Real images of the object are obtained on the screen for two positions of the lens that are separated by distance x apart. The ratio of size of the images in the two positions of the lens are

Show that the minimum distance between the object and the screen is 4 times of focal length of a convex lens at the time of real image formation.

Real image of an object are formed on the fromed on the two positions of a lens separated by a distance 60cm The ratio between the sizes of the two image will be:

The distance between object and the screen is D. Real images of an object are formed on the screen for two positions of a lens separated by a distance d. The ratio between the sizes of two images will be:

The distance between object and the screen is D. Real images of an object are formed on the screen for two positions of a lens separated by a distance d. The ratio between the sizes of two images will be:

If the distance D between an object and screen than 4 times the focal length of a convex lens, then there are two positions of the lens for which image are formed on the screen. This method is called conjugate method. If d is the distance between the two positions of the lens, obtain the equation for focal length of the convex lens.

Real image of an object are formed on the fromed on the two positions of a lens separated by a distance 60cm If the distance between object and screen is 180cm then ,the focal length of the lens is: