int_(0)^((pi)/(2))log(cos x)dx

int_(0)^((pi)/(2))log(sinx)dx=int_(0)^((pi)/(2))log(cosx)dx=(pi)/(2)log.(1)/(2)

int_(0)^((pi)/(2))log(sinx)dx=int_(0)^((pi)/(2))log(cosx)dx=(pi)/(2)log.(1)/(2)

If int_(0)^((pi)/2)log(cosx)dx=-(pi)/2log2 , then int_(0)^((pi)/2)log(cosecx)dx=

If int_(0)^((pi)/2)log(cosx)dx=-(pi)/2log2 , then int_(0)^((pi)/2)log(cosecx)dx=

int_(0)^((pi)/(2))log(sin2x)dx

The value of int_(0)^((pi)/(2))log(tan x)dx is equal to -

Evaluate : int_(0)^((pi)/(2)) log (cot x)dx .

Prove that, int_(0)^(pi)log(1+cos x)dx=-pi log2 , given int_(0)^((pi)/(2))log((sin x))dx=(pi)/(2)"log"(1)/(2) .

int_(0)^((pi)/(2))(2log cos x-log sin2x)dx

The value of int_(0)^((pi)/(2))log[(3+5cos x)/(3+5sin x)]dx is