Projection of U.C.M. along its any diameter is

Show that a linear S.H.M. is the projection of a U.C.M. along any of its diameter.

A linear S.H.M is considered as the projection of a U.C.M. on a diameter of the reference circle. The phase angle between the projections of uniform circular motion on two mutually perpendicular diameter is

If the moment of inertia of a sphere of mass M and radius R about any diameter is m MR^2 , then, what will be its moment of inertia about any tangent?

When a particle performs a U.C.M. of diameter 10cm, its projection along the diameter of the circle, performs a S.H.M. of amplitude

Let bar(u),bar(v),bar(w) be such that |bar(u)|=1, |bar(v)|=2, |bar(w)|=3 If the projection of bar(v) along bar(u) is equal to that of bar(w) along bar(u) and bar(v),bar(w) are perpendicular then |bar(u)-bar(v)+bar(w)|=