A rod of length 3 m has its mass per unit length directly proportional to distance x from one of its ends then its centre of gravity from that end will be at

A rod is of length 3 m and its mass acting per unit length is directly proportional to distance x from its one end. The centre of gravity of the rod from that end will be at

A rod of length 3m and its mass par unit length is directly proportional to the distance x from its one end . The centre of gravity of the rod from that end will be at :-

A rod of length L is of non uniform cross-section. Its mass per unit length varies linearly with distance from left end. Then its centre of mass from left end is at a distance. (Take linear density at left end=0).

A rod of length L is of non uniform cross-section. Its mass per unit length varies linearly with distance from left end. Then its centre of mass from left end is at a distance. (Take linear density at left end=0).

If the linear density (mass per unit length) of a rod of length 3 m is proportional to x , where x , where x is the distance from one end of the rod, the distance of the centre of gravity of the rod from this end is.

A thin bar of length L has a mass per unit length lambda , that increases linerarly with distance from one end. If its total mass is M and its mass per unit length at the lighter end is lambda_(0) , then the distance of the centre of mass from the lighter end is

A thin bar of length L has a mass per unit length lambda , that increases linerarly with distance from one end. If its total mass is M and its mass per unit length at the lighter end is lambda_(0) , then the distance of the centre of mass from the lighter end is

The linear density of a thin rod of length 1m lies as lambda = (1+2x) , where x is the distance from its one end. Find the distance of its center of mass from this end.