[" The displacement at a point due to two waves are "],[y_(1)=4sin(500 pi t)" and "y_(2)=2sin(506 pi t)." The result "],[" due to their superposition will be "]

The displacement at a point due to two waves are y_1=4 sin (500pit) and y_2=2sin(506 pi t) . The result due to their superposition will be

The displacement at a point due to two waves are y_1=4 sin (500pit) and y_2=2sin(506 pi t) . The result due to their superposition will be

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

In case of superposition of waves (at x = 0). y_1 = 4 sin(1026 pi t) and y_2 = 2 sin(1014 pi t)

The displacements of two interfering light waves are y_(1) = 2sin omega t and y_(2) = 5sin (omega t+(pi)/(3)) the resultant amptitude is

Beats are produced by two waves y_(1)=a sin 1000 pi t , y_(2)=a sin 998 pi t The number of beats / sec is

The displacement of two interfering light waves are y_(1)=4 sin omega t" and "y_(2)= 3 cos (omega t) . The amplitude of the resultant waves is (y_(1)" and "y_(2) are in CGS system)