A particle `P` is at the origin starts with velocity `u=(2hati-4hatj)m//s` with constant acceleration `(3hati+5hatj)m//s^(2)`. After travelling for `2s` its distance from the origin is

A particle starts from the origin with velocity vec u= (2hat i - 4 hat j) m/s with constant acceleration (3 hat I + 5 hat j) m/s^2 . After travelling for 2 seconds, its distance from the origin is

A body starts with a velocity (2hati+3hatj+11hatk)m//s and moves with an acceleration (5hati+5hatj-5hatk)m//s^(2) . What is its velocity after 0.2 sec ?

A body starts with a velocity (2hati + 3hatj + 11hatk) m/s and moves with an acceleration (5hati + 5hatj - 5hatk) m//s^(2) . What is its velocity after 0.2 sec ?

A body starts with a velocity (2hati + 3hatj + 11hatk) m/s and moves with an acceleration (5hati + 5hatj - 5hatk) m//s^(2) . What is its velocity after 0.2 sec ?

A particle starts from the origin at t = 0 s with a velocity of 10.0 hatj m/s and moves in plane with a constant acceleration of (8hati + 2hatj)ms^(-2) . The y-coordinate of the particle in 2 sec is

A particle starts from the origin at t = 0 s with a velocity of 10.0 hatj m/s and moves in plane with a constant acceleration of (8hati + 2hatj)ms^(-2) . The y-coordinate of the particle in 2 sec is

A particle starts from the origin at t=Os with a velocity of 10.0 hatj m//s and moves in the xy -plane with a constant acceleration of (8hati+2hatj)m//s^(-2) . What time is the x -coordinate of the particle 16m ?

A particle starts from the origin at t=Os with a velocity of 10.0 hatj m//s and moves in the xy -plane with a constant acceleration of (8hati+2hatj)m//s^(-2) . What time is the x -coordinate of the particle 16m ?