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" 6."root(9)(18)-:root(9)(9)...

" 6."root(9)(18)-:root(9)(9)

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root(3)(2) times root(6)(9)

Arrange the following surds in an ascending order of magnitude: root(3)(9),root(9)(5),root(3)(7)

Arrange in descending order: root(9)(7),root(6)(5),root(3)(2) .

Rationalize the denominator. (3 root(3)(5))/(root(3)(9))

log_(3)root(9)(3)=

Simplify [root(3)(root(6)(2^(9)))]^(4)xx[root(6)(root(3)(2^(9)))]^(4) .

Simplify: [root(3)(root(6)(5^(9)))]^(8)[root(6)(root(3)(5^(9)))]^(8)