Osmotic pressure of `40%` (wt.`//`vol.) urea solution is `1.64 atm` and that of `3.42%` (wt.`//`vol.) cane sugar is `2.46 atm`. When equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution is:

Osmotic pressrue of 0.4% urea solution is 1.64 atm and that of 3.42% cane sugar is 2.46 atm. When the above two solutions are mixed, the osmotic pressure of the resulting solution is

osmotic pressure of 40% urea solution is 1.64 atm and that of 3.42% cane sugar solution is 2.46 atm. When equal volume of the above solutions are mixed, o.p. of resulting solution is …….

If equal volumes of two isotonic solutions are. mixed then calculated the osmotic pressure of the net resultant solution obtained.

100 cc of 1.5% solution of urea is found to have an osmotic pressure of 6.0 atm and 100 cc of 3.42% solution of cane sugar is found to have an osmotic pressure of 2.4 atm. If two solutions are mixed, the osmotic pressure of the resulting solution will be