In the above problem normal reaction between ground and wedge will have magnitude equla to

In the figure if block A and wedge b will move with same acceleration, then the magnitude of normal reaction between the block and the wedge will be (There is no friction between block and the wedge and the wedge moves on horizontal surface as shown.)

In the figure if block A and wedge b will move with same acceleration, then the magnitude of normal reaction between the block and the wedge will be (There is no friction between block and the wedge and the wedge moves on horizontal surface as shown.)

In the above problem, the contact force between the man and the crate is

The work done by the normal reaction on the wedge is :

Consider the shown arrangement. Assume all surfaces to be smooth. If N represents magnitudes of normal reaction between block and wedge, then acceleration of M along horizontal is equla to

A block of mass m is placed on a smooth wedge of wedge angle theta The whole system is accelerated horizontally so that the block does not slip on the wedge. The force (normal reaction) exerted by the wedge on the block has a magnitude:

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a = 5m//s^2 . Let N be the normal reaction between the block and the wedge. Then : (g = 10 m//s^2)