The wavelength of the third line of the Balmer series for a hydrogen atom is -

The wavelength of the first line of the Balmer series of hydrogen atom is lamda . The wavelength of the corresponding line line of doubly ionized lithium atom is

If the wavelength of the first line of the Balmer series of hydrogen atom is 656.1 nm the wavelngth of the second line of this series would be

The wavelength of the first line of Balmer series of hydrogen atom is lambda , the wavelength of the same line in doubly ionised lithium is

The wavelength of the first Balmer line Li^(2+) ion is 136800 cm^(-1) .The wavelength of the first line of Balmer series of hydrogen atom is ("in" cm^(-1))

The wavelength of the first line of Balmer series in hydrogen atom is 6562.8Å . Calculate ionisation potential of hydrogen and also, the wavelength of first line of Lyman series.