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" 24) "(a-2b)^(2)-5(a-2b)+6...

" 24) "(a-2b)^(2)-5(a-2b)+6

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Factorise : (2a + b)^(2) + 5 (2a + b) + 6

Let's resolve into factor:- 6(a + b)^2 + 5(a^2 - b^2)-6(a-b )^2

Factorise: 6a (a -2b ) + 5b (a - 2b )

Simplify the following:(a-2b+5c) (a-b)-(a-b-c) (2a + 3c) + (6a + b) (2c-3a-5b)

If (a)/(b)=(4)/(3), then (3a+2b)/(3a-2b)=?( a) -1 (b) 3 (c) 5(d)6

find roots by Quadratic formula 6(a+b)^(2)x^(2)+5(a+b)x-6c^(2)=0

(2a ^ (2) + 3b ^ (2)) (5a ^ (2) -6b ^ (2))

The sum of the coefficients in the monomials 3a^2b and -2a b^2 is (a)5 (b) -1 (c) 1 (d) -6