[" The resistance of "0.01N" solution "],[" at "25^(@)C" is "200Omega" .Cell constant of "],[" conductivity cell is "1],[cm^(-1)" .The equivalent conductance is "]

The resistance of 0. 01 N NaCl solution at 25^@C is 200 Omega . Cell constant of conductivity cell is 1 cm^(-1) . The equivalent conductnance is .

The resistance of 0.01 N solution at 25^(@)C is 200 ohm. Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

The resistance of 0.01 N solution at 25^(@)C is 200 ohm. Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

At 25^(@)C , the resistance of 0.01 N NaCl solution is 200 ohm . If cell constant of the conductivity cell is unity, then the equivalent conductance of the solution is:

(a) What are the two classifications of batteries ? What is the difference between them ? (b) The resistanc of 0.01 M NaCl solution at 25^(@)C is 200Omega. The cell constant of the conductivity cell is unity. Calculate the molar conductivity of the solution.

(a) What are the two classifications of batteries ? What is the difference between them ? (b) The resistanc of 0.01 M NaCl solution at 25^(@)C is 200Omega. The cell constant of the conductivity cell is unity. Calculate the molar conductivity of the solution.

The resistance of 0.01 M NaCl solution at 25°C is 200 ohm.The cell constant of the conductivity cell used is unity. Calculate the molar conductivity of the solution.

The resistance of 0.01 M NaCl solution at 25°C is 200 ohm.The cell constant of the conductivity cell used is unity. Calculate the molar conductivity of the solution.

The resistance of 0.01N solution of an electrolysis is 210 Omega at 298 K with a cell constant of 0.88 cm^(-1) . Calculate the conductivity and equivalent conducitivty of the solution.

The resistance of 0.01N solution of an electrolysis is 210 Omega at 298 K with a cell constant of 0.88 cm^(-1) . Calculate the conductivity and equivalent conducitivty of the solution.