If the inverse of `P(-3,5)` w.r.t to a circle is `(1,3)` then polar of P w.r.t to the circle is

The polars of two points A(1,3), B(2,-1) w.r.t to circle x^(2)+y^(2)=9 intersect at C then polar of C w.r.t to the circle is

The polars of two points A(1,3), B(2,-1) w.r.t to circle x^(2)+y^(2)=9 intersect at C then polar of C w.r.t to the circle is

Image of (2,3) w.r.t to (-1,3) is

Inverse of (0,0) w.r.t to circle x^(2)+y^(2)-4x-6y+3=0 is

The inverse point of P(4,3) W.r.t the circle x^(2)+y^(2)=25 is

The inverse point of (1,2) w.r.t. the circle x^(2)+y^(2)=25 , is (5,k) then k=

The inverse point of (1,2) w.r.t. the circle x^(2)+y^(2)=25 , is (5,k) then k=

Find the polar of the point (1,2) w.r.t the circle x^2+y^2=7 .