If the degree of ionization of water is `1.8xx10^(-9)` at `298K`. Its ionization constant will be

If the degree of ionization of water be 1.8xx10^(-9) at 298 K . Its ionization constant will be

The degree of dissociation of water is 1.8 xx10^(-9) at 298 K . Calculate the ionization constant and Ionic product of water at 298 K .

The degree of dissociation of water is 1.8 xx 10^(-9) at 298 K. Calculate the ionisation constant and ionic product of water at 298 K

Calculate the degree of ionization of pure water at 25^@C .

What is the pH of 0.001 M aniline solution? The ionization constant of aniline 4.27xx10^(-10) . Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjustant acid of aniline.

What is the pH of 0.001 M aniline solution? The ionization constant of aniline 4.27xx10^(-10) . Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjustant acid of aniline.

What is the pH of 0.001 M aniline solution. The ionization constant of aniline is 4.3× 10^-10.Cálculate the degree of ionization of aniline in the solution. Also calculate the ionization constant for the conjugate acid of aniline?