एक समान्तर चतुर्भुज है सिद्ध कीजिए कि -
` vec(BA) + vec(BC) + vec(CD) + vec(DA) = 2vec(BA)`

The value of vec(AB)+vec(BC)+vec(DA)+vec(CD) is

If ABCD is a quadrilateral, then vec(BA) + vec(BC)+vec(CD) + vec(DA)=

In pentagon ABCDE, prove that : vec(AB)+vec(BC)+vec(CD)+vec(DE)+vec(EA)=vec0 .

ABCDE is a pentagon prove that vec(AB)+vec(BC)+vec(CD)+vec(DE)+vec(EA)=vec0

In a triangle ABC, if taken in order, consider the following statements 1. vec(AB) + vec(BC) + vec(CA) = vec(0) 2 vec(AB) + vec(BC) - vec(CA) = vec(0) 3. vec(AB)- vec(BC) + vec(CA) = vec(0) 4. vec(BA)- vec(BC) + vec(CA) = vec(0) How many of the above statements are correct?

Assertion A : If A, B, C, D are four points on a semi-circular arc with centre at 'O' such that |vec(AB)| = |vec(BC)|=|vec(CD)| , then vec(AB) +vec(AC) +vec(AD) =4 vec(AO) +vec(OB) +vec(OC) Reason R : Polygon law of vector addition yields vec(AB) +vec(BC) +vec(CD) +vec(AD)=2vec(AO) In the light of the above statements, choose the most appropriate answer from the options given below :

In a regular hexagon ABCDEF, vec(AB)=a, vec(BC)=b and vec(CD) = c. Then, vec(AE) =

If A, B, C and D are the vertices of a square, find vec(AB) + vec(BC)+ vec(CD) + vec(DA) .