Home
Class 12
PHYSICS
A point performs simple harmonic oscilla...

A point performs simple harmonic oscillation of period T and the equation of motion is given by `x = a sin (omega t + (pi)/(6))`. After the elapse of what fraction of the time period, the velocity of the point will be equal to half of its maximum velocity ?

Promotional Banner

Similar Questions

Explore conceptually related problems

A point performs simple harmonic oscillation of period T and the equation of motion is given by x = a sin (wt + (pi)/6) . After the elapse of what fraction of the time period the velocity of the point will be equal to half of its maximum velocity ?

A point simple harmonic oscilation of the period and the equation of motion is given by x a sin (omega t + pi //6) after the step of friction of the time period the velocity of the part will be equal to half of its maximum velocity?

The initial phase of a simple harmonic oscillator is zero. At what fraction of the period, the velocity is half of its maximum value?

A simple harmonic oscillator has amplitude A and time period T. Its maximum speed is………………

The equation of motion of a particle executing SHM is x=asin(omegat+pi/6) with time period T. Find the time interval at which the velocity is being half of its maximum value.

A particle undergoes simple harmonic motion having time period T. The time taken in 3/8th oscillation is