x-y+z=1
2x+y-z=2
x-2y-z=4

2x+y-z=1 x-y+z=2 3x+y-2z=-1

The values of x, y, z for the equations x-y+z=1, 2x-y=1, 3x+3y-4z=2 are

2x+y+z=1x-y+2z=-1,3x+2y-z=4

x+y+z=4 2x-y+z=-1 2x+y-3z=-9

If |y z-x^2z x-y^2x y-z^2x z-y^2x y-z^2y z-x^2x y-z^2y z-x^2z x-y^2|=|r^2u^2u^2u^2r^2u^2u^2u^2r^2| , then r^2=x+y+z b. r^2=x^2+y^2+z^2 cdotu^2=y z+z x+x y d. u^2=x y z

What should be added to x y+y z+z x to get x y-y z-z x ? -2x y-2y z-2z x (b) -3x y-y z-z x -3x y-3y z-3z x (d) 2x y+2y z+2z x

Multiply: x^2+4y^2+z^2+2x y+x z-2y z\ by x-2y-z