If `hata and hatb` are unit vectors inclined at angle `theta` then `(1)/(2)|hata+hatb|` is

If hata and hatb are unit vectors inclined at an angle theta then prove that tan "" theta /2 = | (hata -hatb)/(hata+hatb)|

If hata and hatb are unit vectors inclined at an angle theta then prove that cos "" theta /2 = 1/2 |hata + hatb|

If hata and hatb are two unit vectors inclined at an angle theta , then the value of |hata-hatb| is -

If hata and hatb are unit vectors and theta is the angle between them show that sin (theta/2)= 1/2 |hata-hatb|

IF hata + hatb = hatc [ hata , hatb , hatc are unit vectors ] find the angle between hata and hatb .

Unit vector hata and hatb are perpendicular to each other and the unit vector hatc is inclined at an angle theta to both hata and hatb If hatc=m(hata+hatb)+hatn(hata times hatb) . And m,n are real prove that pi/4 le theta le (3pi)/4 .

If hata and hatb are two unit vectors and theta is the angle between them then vector 2hatb+hata is a unit vector if (A) theta= pi/3 (B) theta=pi/6 (C) theta=pi/2 (D) theta=pi