In a right angled triangle ABC, the hypotenuse AB =p, then `vec(AB).vec(AC) + vec(BC).vec(BA)+vec(CA).vec(CB)` is equal to:

If in a right-angled triangle A B C , the hypotenuse A B=p ,then vec(AB).vec(AC)+ vec(BC). vec(BA)+ vec(CA).vec(CB) is equal to 2p^2 b. (p^2)/2 c. p^2 d. none of these

If in a right-angled triangle A B C , the hypotenuse A B=p ,then vec(AB).vec(AC)+ vec(BC). vec(BA)+ vec(CA).vec(CB) is equal to 2p^2 b. (p^2)/2 c. p^2 d. none of these

If in a right-angled triangle A B C , the hypotenuse A B=p ,then vec(AB).vec(AC)+ vec(BC). vec(BA)+ vec(CA).vec(CB) is equal to 2p^2 b. (p^2)/2 c. p^2 d. none of these

If in a right-angled triangle ABC, hypotenuse AC=p, then what is vec(AB).vec(AC)+vec(BC).vec(BA)+vec(CA).vec(CB) equal to ?

In a right angled triangle hypotenuse AC= p, then vec(AB). vec(AC ) + vec(BC) .vec(BA) + vec(CA). vec(CB) equal to ?

If in a right-angled triangle ABC, the hypotenuse AB=p, then vec AB.AC+vec BC*vec BA+vec CA.vec CB is equal to 2p^(2) b.(p^(2))/(2) c.p^(2) d.none of these

If ABCDE is a pentagon, then vec(AB) + vec(AE) + vec(BC) + vec(DC) + vec(ED) + vec(AC) is equal to

If ABCDE is a pentagon, then vec(AB) + vec(AE) + vec(BC) + vec(DC) + vec(ED) + vec(AC) is equal to

The value of vec(AB)+vec(BC)+vec(DA)+vec(CD) is