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" 13.यदि (If) "A=[[cos2 theta,sin2 theta...

" 13.यदि (If) "A=[[cos2 theta,sin2 theta],[-sin2 theta,cos2 theta]],A^(2)" निकालें (find "A^(2)" ) "

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(sin2 theta)/(1-cos2 theta)

cos theta+sin theta=cos2 theta+sin2 theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)

(sin2 theta)/(1+cos2 theta)=

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta

Inverse of the matrix [[cos2 theta,-sin2 thetasin2 theta,cos2 theta]] is