A 1000 kg lift is supported by a cable that can support 2000 kg. The shortest distance in which the lift can be stopped when it is descending with a speed of `2.5 m//s` is `( g = 10 m//s^(2))`

A lift of mass m is supported by a cable that can with stand a force of 3mg. Find the shortest distance in which the lift can be stopped when it is descending with a speed of g/4.

A 25 kg lift is supported by a cable. The acceleration of the lift when the tension in the cable is 175 N, will be -

When a liftman takes 5 persons in a lift, the totla mass of the lilft and the 5 persons becomes 800 kg. What is the tension in the supporting cable, if the lift ascends with an acceleration of 2m//s^(2) ? (g=10m//s^(2)

The mass of a lift is 500 kg. What will be the tension the cable of the lift when it is going up with an acceleration of 2 ms^-1 ?

A man standing in a lift holds a spring balance with a load of 5 kg suspended from it What would be the reading of the balance when the lift is descending with an acceleration of 3.8 m//s^(2) .