If PR = RQ, then :

In triangle ABC , P and Q are the middle points of the sides AB and AC respectively. R is a point on the segment PQ such that PR: RQ =1: 2. If PR = 2cm, then BC =? triangle ABC में, P और Q क्रमशः भुजाओं AB तथा AC के मध्य बिंदु हैं। R, PQ पर एक बिंदु इस प्रकार है कि PR: RQ =1: 2 यदि PR=2 सेमी, तो BC=

two tangents RQ and RP are drawn from an external point R to the circle with centre O. If /_PRQ =120^@ , then prove that OR= PR+ RQ

PQRS is a rectangle. Find angle SP R ? Find angle P RQ. If PR=30 then find P Qand QR . Calculate the perimeter of the rectangle.

RQ is

RQ is

RQ is

If S is the midpoint of a straight line PQ and R is a point different from S, such that PR = RQ then

In the following figure seg PS_|_ seg RQ , seg QT_|_ seg PR . If RQ=6,PS=6 and PR=12 , then find the QT .