The vapour pressure of water at `23^(@)C` is 19.8 mm. 0.1 mole glucose is dissolved in 178.2g of water. What is the vapour pressure (in mm) of the resultant solution ?

The vapour pressure of water at 23^(@)C is 19.8 mm. 0.1 mole of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm) of the resultant solution?

The vapour pressure of water at 23^(@)C is 19.8 mm of Hg 0.1 mol of glucose is dissolved in 178.2g of water. What is the vapour pressure (in mm Hg) of the resultant solution?

When 0.1 mole of glucose is dissolved in 10 mole of water, the vapour pressure of water is

The vapour pressure of water at 20^@C is 17.5mmHg .if 18g of glucose (C_(6)H_(12)O_(6) is added to 178.2g of water at 20^@C , the vapour pressure of the resulting solution will be,

The vapour pressure of water at 20^@C is 17.5mmHg .if 18g of glucose (C_(6)H_(12)O_(6) is added to 178.2g of water at 20^@C , the vapour pressure of the resulting solution will be,

The vapour pressure of water at 25^(@)C is 18 mmHg. If 18 g of glucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water at 20^(@)C , the vapour pressure of the resulting solution will be :

The vapour pressure of water at 25^(@)C is 18 mmHg. If 18 g of glucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water at 20^(@)C , the vapour pressure of the resulting solution will be :