Let `f(x) = min [ tan x, cot x, 1sqrt3]` for all `x in (0, pi/2)`Then the area bounded by y = f (x) and the X - axis is

Let f(x) = minimum (tan x, cot x, 1//sqrt(3) ) AA x in [0, pi//2] . Then area bounded by y = f(x) and the x-axis is log ((a)/(b)) + (pi)/(c sqrt(d)) , then a + b - c + d = _______

Let f(x) = minimum (x+1, sqrt(1-x))" for all "x le 1. Then the area bounded by y=f(x) and the x-axis is

Let f(x) = minimum (x+1, sqrt(1-x))" for all "x le 1. Then the area bounded by y=f(x) and the x-"axis" is

Let f(x)= minimum (x+1,sqrt(1-x) for all x<=1 then the area bounded by y=f(x) and the x -axis,is

Let f(x) = minimum (x+1, sqrt(1-x))" for all "x le 1. Then the area bounded by y=f(x) and the x-"axis" is

Let f(x)=min.[tanx, cotx, 1/sqrt(3)], x in [0, pi/2] . If the area bounded by y=f(x) and x-axis is ln(a/b)+pi/(6sqrt(3)) , where a,b are coprimes. Then ab =…..

Let f(x)=min.[tanx, cotx, 1/sqrt(3)], x in [0, pi/2] . If the area bounded by y=f(x) and x-axis is ln(a/b)+pi/(6sqrt(3)) , where a,b are coprimes. Then ab =…..

Let f(x)=min (x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is (a) 7/3 sq units (b) 1/6 sq units (c) (11)/6 sq units (d) 7/6 sq units

Let f(x)=min (x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is (a) 7/3 sq units (b) 1/6 sq units (c) (11)/6 sq units (d) 7/6 sq units