If an alternating current i = `i_(m )sinomegat` is flowing through an inductor then voltage drop `DeltaV_(L)` across inductor L will be-

If an alternating current i = i_(m) sin omegat is flowing through a capacitor then voltage drop Delta V_(C) across capacitor C will be

If alternating current of 60 Hz frequency is flowing through inductance of L = 1 mH and drop in DeltaV_(L) is 0.6 V then alternating current-

Alternating current through an inductor lags behind the alternating voltage by 90^(@) . What does it imply ?

The current through inductor of 2H is given by l=2t cos 2t . The voltage across the inductor is

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

The current through inductor of 2H is given by I=2t cos 2t . The voltage across the inductor is

An alternating voltage is connected in series with a resistor R and an inductor L. If the potential drop across the resistor is 200 V and across the inductor is 150 V, then what is the applied voltage ?