If the area bounded by the curve `y=sin2x` and lines `x=pi/6` ,`x=a` and x-axis is equal to `1/2` then a is

Area bounded by the curve y=sin^(2)x and lines x=(pi)/(2),x=pi and X-axis is

The value of a for which the area of the region bounded by the curve y = sin 2x , the straight lines x = pi//6, x = a and x-axis is equal to 1/2 is-

The area bounded by the curve y = sin2x, axis and y=1, is

The area bounded by the curve y = sin2x, axis and y=1, is

The area bounded by the curve y = sin x , x in [0,2pi] and the x-axis is equal to

The area bounded by the curve y = sin x , x in [0,2pi] and the x -axis is equal to:

The area bounded by the curve y=x(x^(2)-1) and x-axis is

The area bounded by the curve y = sin x, pi le x le 2 pi and the x-axis is

Area bounded by the curve y=x sin x and x -axis between x=0 and x=2 pi is :

Find the area bounded by the curve y=sin^(-1)x and the line x=0,|y|=pi/2dot