सिद्ध कीजिए कि `(sin theta)/(sin(90^(@)-theta))+(cos theta)/(cos(90^(@)-theta))=sec theta*"cosec" theta`.

Without using trigonometrical tables; prove (sin theta)/(sin(90-theta))+(cos theta)/(cos(90^(@)-theta))=sec theta*cosec theta

sin theta cos(90^(@)-theta)+cos theta sin(90^(@)-theta)

sin theta cos(90^@ -theta) +cos theta sin(90^@ -theta) = ?

Prove the following: sin theta sin(90^(@)-theta)-cos theta cos(90^(@)-theta)=0

Prove the following: sin theta sin(90^(@)-theta)-cos theta cos(90^(@)-theta)=0

sin(270^(@)-theta).sin(90^(@)-theta)-cos(270^(@)-theta).cos(90^(@)+theta)=

(cos theta)/(sin(90^(@)+theta))+(sin(-theta))/(sin(180^(@)+theta))-(tan(90^(@)+theta))/(cot theta)

(sin theta)/(cosec theta)+(cos theta)/(sec theta)=1

Prove that (cos(90^(@)-theta))/(1+sin(90^(@)-theta))+(1+sin(90^(@)-theta))/(cos(90^(@)-theta))=2cosec theta

sin theta cos (90^(@) - theta) + cos theta sin ( 90^(@)-0)= ________