Let `F_1, F_2` are the foci of the ellipse `4x^2 + 9y^2 = 36` and P is a point on ellipse such that `PF_1 = 2PF_2`, then the area of triangle `PF_1F_2` is

The coordinates of the foci of the ellipse 4x^(2) + 9y^(2) = 1 are

F_(1) and F_(2) are the two foci of the ellipse (x^(2))/(9) + (y^(2))/(4) = 1. Let P be a point on the ellipse such that |PF_(1) | = 2|PF_(2)| , where F_(1) and F_(2) are the two foci of the ellipse . The area of triangle PF_(1)F_(2) is :

F_(1) and F_(2) are the two foci of the ellipse (x^(2))/(9) + (y^(2))/(4) = 1. Let P be a point on the ellipse such that |PF_(1) | = 2|PF_(2)| , where F_(1) and F_(2) are the two foci of the ellipse . The area of triangle PF_(1)F_(2) is :

F_(1) and F_(2) are the two foci of the ellipse (x^(2))/(9) + (y^(2))/(4) = 1. Let P be a point on the ellipse such that |PF_(1) | = 2|PF_(2)| , where F_(1) and F_(2) are the two foci of the ellipse . The area of triangle PF_(1)F_(2) is :

Let F_1,F_2 be two foci of the ellipse x^2/(p^2+2)+y^2/(p^2+4)=1 . Let P be any point on the ellipse , the maximum possible value of PF_1 . PF_2 -p^2 is

Let the foci of the ellipse (x^(2))/(9) + y^(2) = 1 subtend a right angle at a point P . Then the locus of P is _

Let PSP ^(1) is a focal chord of the ellipse 4x^(2) +9y^(2) =36 and SP =4 , then S^(1) P^(1) =

Let F1,F_2 be two focii of the ellipse and PT and PN be the tangent and the normal respectively to the ellipse at ponit P.then

Let d be the perpendicular distance from the centre of the ellipse x^2/a^2+y^2/b^2=1 to the tangent drawn at a point P on the ellipse. If F_1 & F_2 are the two foci of the ellipse, then show the (PF_1-PF_2)^2=4a^2(1-b^2/d^2) .