If a body is taken to a place where there is no gravity, then

A seconds' pendulum is taken to a place where acceleration due to gravity falls to one-fourth. How is the time period of the pendulum affected, if at all ? Give reason. What will be its new time period ?

Statement I : A body floats in a liquid with a fraction n of its volume above the surface of the liquid. If the system is taken to a planet where the acceleration due to gravity is greater than that on earth, the fraction n will decrease. Statement II : For flotation, the weight of the body is equal to the weight of the liquid displaced.

If the same body is taken to places having different gravitational field strength, then what will vary: its weight or mass?

A body attached to a spring balance weighs 10 kg on the Earth. The body attached to the same spring balance is taken to a planet where gravity is half that of the Earth. The balance will read

How does angle of dip vary if one goes from a place where acceleration due to gravity is maximum to a place where acceleration due to gravity is minimum?

The acceleration due to gravity decreases by Deltag_(1) when a body is taken to a small height h lt lt R. The acceleration due to gravity decreases by Deltag_(2) when the body is taken to a depth h from the surface off the earth, then (R= Radius of the earth)

Time period of simple pendulum of length l at a place, where acceleration due to gravity is g and period T. Then period of simple pendulum of the same length at a place where the acceleration due to gravity 1.02 g will be

Determine the length of a seconds pendulum at a place, where the acceleration due to gravity is 9.77 frac(m)(s^2)

A pendulum clock giving correct time at a place where g=9.800 ms^-2 is taken to another place where it loses 2 seconds during 24 hours. Find the value of g at this new place.