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Complete the decay reaction .10Ne^(23) t...

Complete the decay reaction `._10Ne^(23) to?+._-1e^0+?`
Also, find the maximum KE of electrons emitted during this decay. Given mass of `._10Ne^(23)=22.994465 u`. mass of `._11Na^(23)=22.989768u`.

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Complete the decay reaction ._10Na^(23) to?+._-1e^0+? Also, find the maximum KE of electrons emitted during this decay. Given mass of ._10Na^(23)=22.994465 u . mass of ._11Na^(23)=22.989768u .

The nucleus ._(10)^(23)Ne decays by beta - emission. Write down the beta - decay. Write down the beta - decay equation and determine the maximum kinetic energy of the electrons emitted. Given that : m(._(10)^(23)Ne)=22.994466 u m(._(11)^(23)Na)=22.089770 u .

The nucleus .^(23)Ne deacays by beta -emission into the nucleus .^(23)Na . Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given, (m(._(10)^(23)Ne) =22.994466 am u and m (._(11)^(23)Na =22.989770 am u . Ignore the mass of antineuttino (bar(v)) .

In beta decay, ""_(10)Ne^(23) is converted into ""_(11)Na^(23) . Calculate the maximum kinetic energy of the electrons emitted, given atomic masses of ""_(10)Ne^(23) and ""_(11)Na^(23) arc 22.994466 u and 22.989770 u, respectively.

A nucleus ""_(10)Ne^(23) undergoes beta - decay and becomes ""_(11)Na^(23) . Calculate the maximum kinetic energy of electrons emitted assuming that the daughter nucleus and antineutrino carry negligible kinetic energy. Given mass of ""_(10)Ne^(23) = 22.994466 u and mass of ""_(11)Na^(23) = 22.989770 m

The nucleus "_10^23Ne decays by beta^- emission. Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that: m ( "_10^23 Ne ) = 22.994466 u m ( "_11^23 Na ) = 22.989770 u.

The nucleus ""_(10)^(23)Ne decays by beta^(-) emission. Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that : m (""_(10)^(23) Ne) = 22.994466 u m (""_(11)^(23)Na) = 22.989770 u .

The nucleus ""_(10)^(23)Ne decays by beta^(-) – mission. Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that: m (""_(10)^(23)Ne ) = 22.994466 u m (""_(11)^(23)Na ) = 22.989770 u.